I think this is the most fitting place to post this so here it goes. I am trying to find the torque produced by the 353. Since torque is a unit of measurement of force over a distance (pound-feet) I would assume that this can be worked backwards to find the "force" side of the equation.
Given the tractive effort of the 353, which is 31,200 pounds and
Given the wheel diameter of the same, 51 inches (4.25 feet)
By finding the circumference of the wheel with a diameter of 51 inches (4.25 feet) and
multiplying the circumference by the force in pounds would produce pound-feet
First we must convert inches to feet 51/12= 4.25 feet
then we find circumference C as per the equation C=pi*Diameter
3.14*4.25=13.345
so to find the torque of the 353 over one complete revolution, we would take the tractive effort, 31200 lbs and multiply by the circumference of the drivers, 13.345 to get 416346 foot pounds
31200*13.345=416346
Am I using the correct distance though? is the circumference the right unit for distance or do I have to use the diameter or radius of the wheels?
If I take the diameter of the drivers 4.25 feet and multiply by 31,200 I get 132,600 foot pound force
If I take the radius of the drivers 2.125 feet and multiply by 31,200 I get 66,300 foot pound force.
If I take the circumference of the drivers, 13.345 and multiply by 31,200 I get 416,364 foot pound force.
Which, if any is the most correct?
Given the tractive effort of the 353, which is 31,200 pounds and
Given the wheel diameter of the same, 51 inches (4.25 feet)
By finding the circumference of the wheel with a diameter of 51 inches (4.25 feet) and
multiplying the circumference by the force in pounds would produce pound-feet
First we must convert inches to feet 51/12= 4.25 feet
then we find circumference C as per the equation C=pi*Diameter
3.14*4.25=13.345
so to find the torque of the 353 over one complete revolution, we would take the tractive effort, 31200 lbs and multiply by the circumference of the drivers, 13.345 to get 416346 foot pounds
31200*13.345=416346
Am I using the correct distance though? is the circumference the right unit for distance or do I have to use the diameter or radius of the wheels?
If I take the diameter of the drivers 4.25 feet and multiply by 31,200 I get 132,600 foot pound force
If I take the radius of the drivers 2.125 feet and multiply by 31,200 I get 66,300 foot pound force.
If I take the circumference of the drivers, 13.345 and multiply by 31,200 I get 416,364 foot pound force.
Which, if any is the most correct?